Question

suppose geographic areas of California and the u.s. are 1.637×10^5 and 3.794×10^6 sq.mi,respectively. California's population is approximately 3.804×10^7 people.if population were proportional to area,what would the u.s. population?the actual population of the u.s. is approximately 3.14×10^8. how does the population density of California compare with the population density os the u.s.

Answer 1

Problem

suppose geographic areas of California and the u.s. are 1.637×10^5 and 3.794×10^6 sq.mi,respectively. California's population is approximately 3.804×10^7 people.if population were proportional to area,what would the u.s. population?​

the actual population of the u.s. is approximately 3.14×10^8. how does the population density of California compare with the population density os the u.s.

Solution

For this case we can use the following proportional rule:

`\frac{3.794x10^6\text{sqmi}}{1.637x10^5\text{sqmi}}=\frac{x}{3.804x10^7\text{people}}`

And solving for x we got:

`x=(3.804x10^7)/(1.637x10^5sqmi)\cdot3.794x10^6sqmi=8.816x10^8people`

We can calculate the density for each case and we got:

US:

`D=\frac{3.14x10^8\text{people}}{3.794x10^6\text{sqmi}}=82.762`

California

`D=\frac{3.804x10^7\text{people}}{1.637x10^5\text{sqmi}}=232.376`

Then we can conclude that the density of California is more than the density of US