Part A
g(9) = 6
g(49) = 14
The rate of change g(x) over the interval [9,49] is:
![(g(49)-g(9))/(49-9)=(14-6)/(40)=(8)/(40)=(1)/(5)](https://img.qammunity.org/2023/formulas/mathematics/college/y96zhitups8pqv46nywv7g7wahydede8cb.png)
Likewise:
g(25)=10
g(81)=18
The rate of change of g(x) over the interval [25,81] is:
![\frac{g(81)-g(25)_{}}{81-25}=(18-10)/(56)=(8)/(56)=(1)/(7)](https://img.qammunity.org/2023/formulas/mathematics/college/ogtadvqnswz5y8wzxlhqcvsrikha1ca2p1.png)
The difference will be:
![\begin{gathered} =(1)/(5)-(1)/(7) \\ =0.06\text{ (to the nearest hundredth)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qeyfgs6y7dr8y4y26txag0vm3h7cai7arn.png)
Part B
g(121)=11 x 2=22
g(225)= 15 x 2 =30
Therefore, the rate of change over the interval [121,225]
![=(g(225)-g(121))/(225-121)=(30-22)/(104)=(8)/(104)=(1)/(13)](https://img.qammunity.org/2023/formulas/mathematics/college/qzrn2nagxy3jidfyiltc1jk2dmxjkic93d.png)