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Find the ratios for cos A and sin B.A543Not drawn to scalecos A =sin B:B

Find the ratios for cos A and sin B.A543Not drawn to scalecos A =sin B:B-example-1
User Arumand
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Answer

cos A = 4/5

sin B = 4/5

Explanation

Cosine formula


\cos(angle)=\frac{adjacent\text{ side}}{hypotenuse}

Considering angle A, the adjacent side is AC and the hypotenuse of the triangle is AB, then:


\begin{gathered} \cos(A)=(AC)/(AB) \\ \cos(A)=(4)/(5) \end{gathered}

Sine formula


\sin(angle)=\frac{opposite\text{ side}}{hypotenuse}

Considering angle B, the opposite side is AC and the hypotenuse of the triangle is AB, then:


\begin{gathered} sin(B)=(AC)/(AB) \\ s\imaginaryI n(B)=(4)/(5) \end{gathered}

User Wolfgang Ulmer
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