Answer:
There are 0.26 moles of neon.
Step-by-step explanation:
From the information in the exercise we know that:
- Volume (V): 2.00L
- Temperature (T): 300.0K
- Pressure (P): 3.25atm
Using the Ideal Gases Law formula, we can calculate the number of moles (n), by replacing the values of V, T and P:
![\begin{gathered} P*V=n*R*T \\ 3.25atm*2.00L=n*0.082(atm*L)/(mol*K)*300.0K \\ 6.5atm*L=n*24.6(atm*L)/(mol) \\ (6.5atm*L)/(24.6(atm*L)/(mol))=n \\ 0.26mol=n \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/ck5mz4ihndiztbowksl3rrj0ruuu6vy05i.png)
So, there are 0.26 moles of neon (0.3 rounded).