Question

4x^2+6x=18 quadratic formula roots

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

4x² + 6x = 18

Step 02:

quadratic formula:

4x² + 6x = 18

4x² + 6x - 18 = 0

a = 4

b = 6

c = - 18

`x\text{ =}(-b\pm√(b^2-4ac))/(2a)`
`x\text{ =}(-6\pm√((6)^2-4(4)(-18)))/(2(4))=(-6\pm√(36+288))/(8)=(-6\pm√(324))/(8)`
`\begin{gathered} x1\text{ = }(-6+18)/(8)=(12)/(8)=(3)/(2) \\ \\ x2=(-6-18)/(8)=(-24)/(8)=-3 \end{gathered}`

The answer is:

x1 = 3 / 2

x2 = - 3