Given the Kinetic energy of a toy car, K.E.=04.J
To find new Kinetic energy, K.E.' when speed is doubled.
Kinetic energy is given by the formula,
![K\mathrm{}E\mathrm{}=(1)/(2)mv^2](https://img.qammunity.org/2023/formulas/physics/college/dtxjhdb967jfalf6voe5wfpi8bh3ecb5d8.png)
Here, m is the mass and v is the speed.
Now, if the new speed v'=2v, then new kinetic energy will be
![\begin{gathered} KE^(\prime)=(1)/(2)mv^(\prime2) \\ \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/i1001dr127ginrymvrhxftp5wq6vhagcav.png)
![\begin{gathered} K\mathrm{}E\mathrm{}^(\prime)=(1)/(2)m(2v)^2 \\ =(1)/(2)m*4v^2 \\ =4*(1)/(2)mv^2 \\ =4* K.E. \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/d5sucrs2ald2xic9eh8bgbu771779kpgxu.png)
Substituting the value of K.E. in the above equation, we get
![\begin{gathered} K\mathrm{}E\mathrm{}^(\prime)=4*0.4 \\ =1.6\text{ J} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/m0hcx2vtqibrgtslyo7yu5ohxcnp7b18em.png)
Thus, the new kinetic energy will be 4 times of initial kinetic energy and its value will be 1.6 J when speed is doubled.