1 Answer

Mike Gledhill · Answer 1 · 2023-02-26T22:56:43+0000

We need to find a perfect square from the expression

In this regard, we can note that

Then, by comparing this result with our expression, we can see that the blank space is 1 because

$y^2-2y+1=\left(y-1\right)^2$

Therefore, the answer is:

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