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Aluminum bromide can be prepared by reacting small pieces of aluminum foil with liquid bromine at room temperature. The balanced chemical reaction is:2Al(s) + 3Br2(l) → 2AlBr3(s)How many moles of Br2 are needed to produce 5 mol of AlBr3, if sufficient Al is present?Select one:a.22.1b.17c.7.5

User Ygg
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Answer

7.5 mol Br₂

Procedure

Considering that the equation is already balanced we will use the reaction stoichiometry to solve the problem as follows


5\text{ mol AlBr}_3\frac{3\text{ mol Br}_2}{2\text{ mol AlBr}_3}=7.5\text{ mol Br}_2

User IGRACH
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