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26 votes
26 votes
Allison invested $70,000 in an account paying an interest rate of 6.2%

compounded continuously. Assuming no deposits or withdrawals are made,
how long would it take, to the nearest year, for the value of the account to
reach $223,200?

User StephanS
by
3.1k points

2 Answers

19 votes
19 votes

Using the formula for continuous compounding, A = Pe^(rt), it will approximately take 20 years for Allison's investment of $70,000 at an interest rate of 6.2% compounded continuously to grow to $223,200.

To calculate how long it will take for Allison's investment to grow to a specific amount with continuous compounding interest, we use the formula for continuous compounding, which is A = Pert, where:

A is the amount of money accumulated after n years, including interest.

P is the principal amount (the initial amount of money).

e is the base of the natural logarithm (~2.71828).

r is the annual interest rate (in decimal).

t is the time in years.

Here, we want to find t when A is $223,200, P is $70,000, and r is 0.062 (which is 6.2% expressed as a decimal).

The formula will look like this:

$223,200 = $70,000e0.062t

First, we divide both sides by $70,000:

e0.062t = 3.18857143

Next, we take the natural logarithm of both sides to solve for t:

ln(e0.062t) = ln(3.18857143)

0.062t = ln(3.18857143)

t = ln(3.18857143) / 0.062

t ≈ 20.03 years

Therefore, to the nearest year, it will take approximately 20 years for Allison's investment to grow to $223,200 at an interest rate of 6.2% compounded continuously.

User Rene Korss
by
3.2k points
24 votes
24 votes

Answer: 19

Step-by-step explanation: j trust me

User Tgharold
by
3.7k points
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