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16х2 +10x - 27 - бх +5What are the solutions to this equation? (the 16x2, the two is squared)

User Ivan Wang
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1 Answer

5 votes

16х² +10x - 27 - бх +5 = 0

16х² + (10x - 6x) + (-27 + 5) = 0 combinig similar terms

16х² + 4x - 22 = 0

Using quadratic formula,


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User Evans Murithi
by
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