I need help to find the nearest tenth of this triangle. I've been struggling for about 30 minutes now. I will include the photo!

Question

asked Jul 28, 2023 1.9k views

1 Answer

← Prev Question Next Question →

Ask a Question

Dkarzon · Answer 1 · 2023-08-01T08:12:02+0000

Area of the triangle PQR can be determined as,

$\begin{gathered} \Delta=(1)/(2)* QP* RS \\ =(1)/(2)*8\text{ cm}* RP\sin 39^(\circ) \\ =(1)/(2)*8\text{ cm}*15\operatorname{cm}*\sin 39^(\circ) \\ =37.759cm^2 \end{gathered}$

Thus, the required area of the triangle to the nearest tenth is 37.8 square centimeters.

I need help to find the nearest tenth of this triangle. I've been struggling for about-example-1

I need help to find the nearest tenth of this triangle. I've been struggling for about 30 minutes now. I will include the photo!

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

No related questions found

Categories

Other Questions