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Dkarzon · Answer 1 · 2023-08-01T08:12:02+0000

Area of the triangle PQR can be determined as,

$\begin{gathered} \Delta=(1)/(2)* QP* RS \\ =(1)/(2)*8\text{ cm}* RP\sin 39^(\circ) \\ =(1)/(2)*8\text{ cm}*15\operatorname{cm}*\sin 39^(\circ) \\ =37.759cm^2 \end{gathered}$

Thus, the required area of the triangle to the nearest tenth is 37.8 square centimeters.

I need help to find the nearest tenth of this triangle. I've been struggling for about-example-1

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