4.7k views
1 vote
What does the value of f(x)=(1+1/x)^x approach as x approaches infinity?

1 Answer

4 votes

In order to determine the value of f(x) as x approaches to oo, replace larger values of x into the function and identify the tendency of f(x), as follow:

x = 1000


f(1000)=(1+(1)/(1000))^(1000)\approx2.7169

x = 1000000


f(1000000)=(1+(1)/(1000000))^(1000000)\approx2.7182

x=1000000000


f(1000000000)=(1+(1)/(1000000000))^(1000000000)\approx2.7182

As you can notice, as x approaches to oo, f(x) approaches to 2.7182..., which is the value of constant e.

answer: e

User Mobibob
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories