Question

(The question is in the photo Sorry lol) A 21 L tank contains a gas under a pressure of 367 atm. What volume would the gas occupy at the same temperature at 630 torr of pressure?Answer in units of L.✨Please leave all the numbers after the decimal in the final answer

Answer 1

Again, this is Boyles Law, since we want V2 from given:

V1 = 21 L

P1 = 367 atm

P2 = 630 torr = 0.828947 atm

V2 = ?

Remember to covert torr to atm so that the units are the same and can cancel one another.

1 torr = 0,00131579 atm

630 torr = 0.828947 atm

And the temperature is constant, so we do not need to use it.

P1V1 = P2V2

V2 = P1V1/P2

V2 = (367 atm x 21 L)/0.828947 atm

V2 = 9297.337465 L