We have the point
A(-6,2)
a) In order to find the coordinates of the A' when A is reflected across y=x we have the next rule
![(x,y)\rightarrow(y,x)](https://img.qammunity.org/2023/formulas/mathematics/college/xrxzofqrju7bzvtyrl9rd71hrft58h54y4.png)
therefore
A'(2,-6)
b) In order to find the coordinates of A' when A is reflected across y=-x we have the next rule
![(x,y)\rightarrow(-y,-x)](https://img.qammunity.org/2023/formulas/mathematics/college/s95jsg87jmmw4ebv3603unayyw5jduolzx.png)
therefore
A'(-2,6)
As we can see in the next image
where y=x is the line in green and the line in blue is y=-x