Question

2) Letter tiles similar to the example here are placed in a bag. There are a total of 8 tiles in the bag containing the following letters: G, I, R, V, I, A, I and N a) What is the probability of selecting an 1, keeping it, then an A?

Answer 1

3/56

Step-by-step explanation:

Total tiles = 8

Number of is in G, I, R, V, I, A, I, N = 3

Probability of selecting I = number of Is/total tiles

`\text{Probability of selecting I = }(3)/(8)`

After selecting I, it is kept before picking A

This means we are picking A without replacing I

`\begin{gathered} \text{Probability of picking A = number of As/total tiles} \\ \text{Probability of picking A =}(1)/(8) \\ \\ \text{SInce I, is not replaced, the total tiles left = 7} \\ \text{Probability of picking A will be = }(1)/(7) \end{gathered}`

Probability of selecting an I, keeping it, then an A:

`\begin{gathered} =(3)/(8)*(1)/(7) \\ =\text{ 3/56} \end{gathered}`