50.1k views
0 votes
Working on a practice test and need a little support on a few

Working on a practice test and need a little support on a few-example-1
User Sam Hanes
by
5.7k points

1 Answer

6 votes

Solution

For this case we can use the following formula:


V=(1)/(3)\pi\cdot r^2\cdot h

And we have that :

r= 8/2= 4in

h = 12 in

Replacing we got:


V=(1)/(3)\pi\cdot(4)^2\cdot12=201.06

then the answer is :

V= 201.06

For the second case we can do this:

2x +35= 5x-22

35+22 = 5x-2x

57 = 3x

x= 57/3= 19

User Hnh
by
6.1k points