Question

At 1:00 PM the water level in a pool's is 13 inches. At 2:30 pm the water level is 28 inches what is the constant rate of change

Answer 1

1/6 or 0.167 inches per minute

Step-by-step explanation

We want to find the constant rate of change of the water level.

To do this, we have to find the difference in water level, find the time taken, then divide the former by the latter.

Difference in water level is:

D = 28 - 13 = 15 inches

The time difference is:

H M

2 : 30

- 1 : 00

1 : 30

That is 1 hour 30 minutes.

In minutes, that is:

(60 * 1) + 30 = 60 + 30 = 90 mins

So, the constant rate of change of water level is:

`\begin{gathered} \text{Rate = }(15)/(90) \\ \text{Rate = 1/6 or 0.167 inches per minute} \end{gathered}`

That is the constant rate of change of water level.