Question

What happened to the number of moles in a sample that originally occupied 550 mL with 3.00 moles and then occupied 845 mL?

Answer 1

Answer;

4.60moles

Explanations:

The number of moles and volume are related to each other by the formula;

`(n_1)/(v_1)=(n_2)/(v_2)=k`

where

n1 and n2 are the initial and final number of moles respectively

v1 and v2 are the initial and final volumes respectively

Given the following parameters

• n1 = 3.00moles

,

• v1 = 550mL = 0.55L

,

• v2 = 845mL = 0.845L

Required

Final mole "n2"

Substitute the given parameters into the formula

`\begin{gathered} n_2=(n_1v_2)/(v_1) \\ n_2=(3*0.845)/(0.55) \\ n_2=(2.535)/(0.55) \\ n_2=4.60moles \end{gathered}`

Hence the number of moles will increase to 4.60moles