1 Answer

Thanos · Answer 1 · 2023-09-28T03:30:29+0000

The surface area of the outside of the block is determined by the difference of cube and cylinder.

The surface area of cylinder is,

$S_c=\text{ 2}\Pi rh+2\Pi(r^2)$

The radius is 2 ft and height is 6 ft.

$S_c=2\Pi(2*6+2^2)$
$S_c=\text{ 2}*3.14*(12+4)$
$S_c=100.48ft^{2^{}}$

The surface area of cube is,

The sidde of cube is 6 ft.

$S_a=\text{ 6}*6^2$
S_a=216ft^2

The surface area of the outside of the block is,

$S=\text{ 216-100.48}$
S=115.52ft^2

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