a)
First term= a1 = 5
common difference = d = 0.5
an= a1 + d (n-1)
an= 5 + 0.5 (n-1)
an= 5 + 0.5n - 0.5
an= 4.5 + 0.5n

b) Sum of terms of an arithmetic series is the average of the first and last, multiplied by the number of terms: the sum must be greater than 60.
dn = n/2 (5 + 4.5 + 0.5n)
n/2 (9.5 + 0.5n) > 60
n (19+n) > 240
n^2 +19n + 9.5^2 > 240 +9.5^2
n+9.5 > √330.25
n> 18.17 -9.5
n> 8.67
Melissa's total distance will first exceed 60 miles the 9th time she trains.