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A weight of 17 N is located at a distance of 8 cm from the fulcrum of a simple balance beam. At what distance from the fulcrum should a weight of 22 N be placed on the opposite side in order to balance
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A weight of 17 N is located at a distance of 8 cm from the fulcrum of a simple balance beam. At what distance from the fulcrum should a weight of 22 N be placed on the opposite side in order to balance the system?

User Sarower Jahan
by
5.7k points

1 Answer

4 votes

W1 = 17N

d1 = 8 cm

W2 = 22N

d2= x

Where:

w= weight

d= distance

W1*d1 = W2*d2

17N*8cm= 22N*x

(17M*8cm)/22N = x

x = 6.19 cm

User Ouah
by
6.3k points
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