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Suppose f (x) = 2x – 5, g(x) = - 3x – 1, and h (x) = 2x^2 + x - 7 Solve: g(x) = -7
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Suppose f (x) = 2x – 5, g(x) = - 3x – 1, and h (x) = 2x^2 + x - 7 Solve: g(x) = -7

User David Kudera
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\begin{gathered} g(x)=-3x-1 \\ g(x)=-7 \\ -7=-3x-1 \\ \text{Add 1 to both sides} \\ -6=-3x \\ \text{Divide both sides by -3:} \\ x=(-6)/(-3) \\ x=2 \end{gathered}

User Antony Carthy
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