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Write a function rule for the area of rectangle whose length is 2ft more than its width. What is the area of the rectangle when its width is 11ft

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According to the problem, the length is 2 feet more than its width, which is expressed as the following function


l=w+2

If the width is x, then the length is x+2.

We can express the following function for the area


A(x)=x(x+2)

Let's replace the width x = 11 ft.


A(11)=11\cdot(11+2)=11(13)=143

Hence, the area is 143 square feet.

The function for the area is


A(x)=x(x+2)

Where x represents the width.

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