INFORMATION:
We have the next reaction
- Ba(NO3)2 + (NH4)3PO4
And we must find its net ionic equation
STEP BY STEP EXPLANATION:
To find the net ionic equation, we must follow the next steps:
1. We must write the balanced equation

2. We must write the states of each substance

3. We must split strong electrolytes into ions

4. We must cross out the spectator ions on both sides
5. Finally, we must write the remaining substances

ANSWER: