The density is a constant ratio between the number of fish and the volume of the tank, that is
![\text{density}=\frac{\#of\text{ fish}}{volumeft^3}=0.5](https://img.qammunity.org/2023/formulas/mathematics/college/j2hk3iatxydp90f7sqzyo88iubislw5vtq.png)
since this ratio must be preserved, then we can write
![\frac{30\text{ fish}}{\text{V}}=0.5](https://img.qammunity.org/2023/formulas/mathematics/college/nsiyjjx85i02izvh5occdhzyh0imy8v0vm.png)
where V denotes the unknown volume. Now, we need to isolate V.
By multiplying both sides by V, we have
![30\text{fish}=V*0.5](https://img.qammunity.org/2023/formulas/mathematics/college/qwx43fdteptxakfusoodvc6674u7mkmwqk.png)
and by dividing both sides by 0.5, we get
![\frac{30\text{ fish}}{\text{0.5}}=V](https://img.qammunity.org/2023/formulas/mathematics/college/ecpt2j9obi9fnepsm5wucalu811xd7bbkq.png)
which gives
![\begin{gathered} V=(30)/(0.5)ft^3 \\ V=60ft^3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rjiwq1a71rf2hag63rgs6zky63hu2lo7ti.png)
Therefore, the answer is option A: 60 cubic feet