Question

Find the x- and y- intercepts of the line represented by the equation 2x-7y=28X=?, y=?

Answer 1

Step-by-step explanation:

The first thing we have to do is find the value of Y,To find the y-intercept when x equals zero,Then we find the x-intercept by setting Y equal to zero

`\begin{gathered} 2x-7y=28 \\ -7y=-2x+28;\text{here we must multiply }by\text{ minis 1 }so\text{ that Y is positive} \\ 7y=2x-28 \\ y=(2x)/(7)-(28)/(7) \\ y=(2x)/(7)-4 \\ \textcolor{#FF7968}{m=(2x)/(7)} \\ \text{\textcolor{#FF7968}{Now Y AXIS intercepts}}\textcolor{#FF7968}{\colon} \\ x=0\text{ y}=-4\text{ }\textcolor{#FF7968}{(0,-4)} \\ \textcolor{#FF7968}{X}\text{\textcolor{#FF7968}{ intercepts:}} \\ y=0\text{ ; then 0}=(2x)/(7)-4 \\ 4=(2x)/(7) \\ 4(7)=(2x)/(7) \\ 28=2x \\ (28)/(2)=x \\ 14=x \\ \textcolor{#FF7968}{x}\text{\textcolor{#FF7968}{ intercepts (}}\textcolor{#FF7968}{14,0)} \end{gathered}`