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Given ABC has interior angle measures with:

User Kitty
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For this exercise it is important to remember the de sum of the interior angles of a triangle is 180 degrees.

For this case, you have the triangle ABC, and according to the information given in the exercise:


\begin{gathered} \angle A=3x-15 \\ \angle B=x+5 \\ \angle C=x-10 \end{gathered}

Knowing the above, you can set up the following equation:


(3x-15)+(x+5)+(x-10)=180

Now you must solve for "x":


\begin{gathered} 3x-15+x+5+x-10=180 \\ 5x-20=180 \\ 5x=180+20 \\ 5x=200 \\ \\ x=(200)/(5) \\ \\ x=40 \end{gathered}

Now, substitute the value of "x" into this equation:


\angle A=3x-15

Evaluating, you get that the measure of the angle A is:


\angle A=3(40)-15=105\degree

The answer is:


\angle A=105\degree

User Jaredpalmer
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