Question

Help in the Accompanying diagram of the circle O chord CD ….

Answer 1

The length of ED is;

`ED=8`

Step-by-step explanation:

Given the figure in the attached image.

Chord CD bisects chord AB at E.

So;

`AE=EB=(AB)/(2)`

Also applying the Bisecting chord formula;

`AE\cdot EB=CE\cdot ED`

Given;

`\begin{gathered} CE=2 \\ AB=8 \\ AE=EB=(AB)/(2)=(8)/(2)=4 \\ AE=4 \\ EB=4 \end{gathered}`

substituting the given values;

`\begin{gathered} AE\cdot EB=CE\cdot ED \\ 4\cdot4=2\cdot ED \\ 16=2\cdot ED \\ ED=(16)/(2) \\ ED=8 \end{gathered}`

Therefore, the length of ED is;

`ED=8`