SOLUTION:
Step 1:
In this question, we are meant to determine the length of x in the triangle.
We are also expected to give your answer to two decimal places, using the diagram below:
Step 2;
Using Pythagoras' theorem, we have that:

Making x, the subject of the formulae, we have that:



CONCLUSION:
The length of x in the triangle = 35. 09 ( two decimal places)