Let x be the number of vans and y the number of cars.
We are told that for every 3 vans we get 5 car. This translates to the equation
![y\text{ = }(5)/(3)x](https://img.qammunity.org/2023/formulas/mathematics/college/maf27twc1ihtjg9xo7fx3nfuaa2hv6l76q.png)
Note that if we replace x=3, we get y=5 which is what we are told.
Now, we have 96 vehicles in total, so
![x+y\text{ = 96}](https://img.qammunity.org/2023/formulas/mathematics/college/t751i3auj1rww4sh6iz7q1gjin6v99qa6b.png)
Now, we replace the value of y with what we found in the first equation, so
![x\text{ + }(5)/(3)x\text{ = 96 = }(8)/(3)x](https://img.qammunity.org/2023/formulas/mathematics/college/abaoqysxxt2ajtcpere7v8pufyqsg8pauf.png)
If we multiply by 3 on both sides, we get
![8x\text{ = 96}\cdot3\text{ = 288 }](https://img.qammunity.org/2023/formulas/mathematics/college/mg5d3o9ald16kpp6wrvy3psqkehcqh5s9h.png)
If we now divide by 8 we get
![x\text{ = }(288)/(8)\text{ = 36}](https://img.qammunity.org/2023/formulas/mathematics/college/ysaspcapeg9llfws8hg7al59ygd6lj8cre.png)
Since x+y = 96 and x = 36, then we must have y = 60.
So, there are 36 vans and 60 cars