Question

Triangle JKL is similar to triangle MNO. find the measure of side NO. Round your answer to the nearest tenth if necessary.

Answer 1

Given Data

`\Delta JKL\cong\Delta MNO`

From the propery of the similar triangles,

`(JK)/(MN)=(KL)/(NO)=(JL)/(MO)`

Substituting the know values in the above equation,

`\begin{gathered} (KL)/(NO)=(JL)/(MO) \\ \Rightarrow(8)/(NO)=(11)/(49) \\ \Rightarrow NO=(8*49)/(11) \\ \Rightarrow NO=35.63 \end{gathered}`

Thus, the requried value of NO nearest to the tenth is 35.6.