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What is the midpoint of line segment EF if E (-5,-1) and F (17,-9)?

User Flaashing
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1 Answer

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STEP 1:

The formula for the midpoint of a line segment


\text{midpoint =(}\frac{x_{1\text{ }}+x_2}{2}),\text{ (}(y_1+y_2)/(2))

STEP 2:

We substitute the following information in the formular.


\begin{gathered} x_1=\text{ -5} \\ x_2=\text{ 17} \\ y_1=\text{ -1} \\ y_2=\text{ -9} \end{gathered}
\begin{gathered} \text{midpoint = (}(-5+17)/(2)\text{),(}(-1+(-9))/(2)\text{)} \\ \text{midpoint =(}(12)/(2)\text{),(}(-10)/(2)\text{)} \\ \text{midpoint = 6,-5} \end{gathered}

In conclusion, midpoint is 6,-5

User Dhruvam Sharma
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