Question

Hi, can you help me answer this question please, thank you

Answer 1

Explanation:

Answer 2

First, find the degrees of freedom.

`df=n-1=53-1=52`

The t-value of 52 degrees of freedom is 2.01.

Then, we use the following formula.

`\bar{x}\pm t\cdot\frac{s}{\sqrt[]{n}}=71.6\pm2.01\cdot\frac{16.6}{\sqrt[]{53}}=71.6\pm4.6`

Therefore, the confidence interval is

`67\leq\mu\leq76.2`