Question

In the following figure, FB−→ bisects (divides into 2 equal parts) ∠DFC and FA−→ bisects ∠EFC. If m∠2=30°, find m∠1.

Answer 1

Given the figure shown:

As shown:

FB bisects ∠DFC

so, m∠1 = m∠2

But, given m∠2=30°

so, m∠1 =30°

So, the answer will be m∠1 = 30°