Let the smaller number be 'x' and the larger number be 'y'.
Given that the sum of the numbers is 60,

Also, given that the larger number is 6 more than the smaller number,

Substitute the value,

Taking the variables and constants on either side,

Divide both sides by 2,

Substitute this value and obtain the other variable,

Thus, the larger number is 33 and the smaller number is 27.