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Find the equation of the line L1 which is perpendicular to the line L2 with the equation y=2x+2022 and passes through point A(2,10)

1 Answer

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Answer:

y = -0.5x + 11

Explanation:

Given:

Equation of line in slope-intercept form as
y = 2x + 2022

Find:

Equation of perpendicular line passing through (2,10)

A line perpendicular to a line y = mx + b where m = slope will have as its slope -1/m

The given line has slope 2
So perpendicular line will have slope - 1/2 = 0.5

Equation of line will be
y = -0.5x + b where b is the y-intercept of the perpendicular line

Since the line passes through (2, 10) we can plug in these values of x = 2 and y = 10 into the perpendicular line equation and solve for b

10 = -0.5 x 2 + b

10 = -1 + b

b = 10 + 1

b = 11

So the equation of the perpendicular line is

y = -0.5x + 11

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