Question

Help me do the graph please I left you some notes in the side

Answer 1

One way to answer this question is by finding the x- and y-intercept of the line, and with these two points, we define the line.

Finding the x-intercept

This point is the point when y = 0. If we have the equation, then:

`y=-(3)/(4)x+2\Rightarrow0=-(3)/(4)x+2\Rightarrow-2=-(3)/(4)x\Rightarrow4\cdot(-2)=-3x`

Now, we have:

`-8=-3x\Rightarrow x=(-8)/(-3)\Rightarrow x=(8)/(3)=2.66666666667=2+(2)/(3)`

Thus, one of the points is (8/3, 0)

Finding the y-intercept

This is the point for y when x = 0. If we have the equation:

`y=-(3)/(4)(0)+2\Rightarrow y=2`

Then, the y-intercept is (0, 2).

Now, we can graph the line as follows:

As we can see the two intercepts, namely, (0, 2) and (8/3, 0) are sufficient to graph the line as we can see above.

[Each division on the graph is equivalent to one unit.]

rcepth