The formula for calculating the orbital speed of the eqrth as it orbits the sun is expressed as
![V\text{ = }\sqrt[]{(GM)/(R)}](https://img.qammunity.org/2023/formulas/physics/high-school/2q9xk67vi23gtgv3icczz8r95on8njhntd.png)
Where
G is the gravitational constant whose value is 6.673 x 10^- 11 Nm^2/kg^2
M is the mass of the central body about which the satelite orbits
R is the ardius of orbit of the satelite
From the information given,
M = 1.99 x 10^30 kg
R = 1.496 x 10^11
By substituting these values into the formula, we have
![\begin{gathered} V\text{ = }\sqrt[]{\frac{6.673\text{ }*10^(-11)*1.99\text{ }*10^(30)}{1.496\text{ }*10^(11)}} \\ V\text{ = 29793.48 m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/high-school/bof9nt1w9a7o83tn7dg2znbw90egpbtqnh.png)
The orbital speed of the Earth, in m/s, as it orbits the Sun is 29793.48 m/s