Question:
Solution:
Notice that the function f(x) = 2-2x is a linear function with slope -2 and y-intercept 2. Then its graph on the given domain is:
Now, the range of the function is found by evaluating the function at the extreme points of the domain. That is:
![f(-1)\text{ = 2-2(-1) = 2+2 = 4}](https://img.qammunity.org/2023/formulas/mathematics/college/ujc4nu19cm3mzb8pb18qayb8j1a6tb0vyu.png)
and
![f(4)\text{ = }2-2(2)\text{ = 2-4 = -}2](https://img.qammunity.org/2023/formulas/mathematics/college/s4gcta6pg995pggbll5wf8302ncz1gklxa.png)
Thus, the range of this function (not taking into account all the real numbers, but with the notation of the exercise) is:
![R\text{ = }\lbrace-2,-1,0,1,2,3,4\rbrace](https://img.qammunity.org/2023/formulas/mathematics/college/kwaiycc7ybfln9wt2itb30qt9750fmscg7.png)