Question

The table below shows the results of a survey asking 48 studentswhat type of pet they prefer.Pet SurveyPreferred Pet # of StudentsDog 20Cat 16Other Pet 5No Pet 7If one student in the survey is selected at random, what is theprobability the student will prefer a cat or a dog?Leave your answer in fraction form.

Answer 1

`P(A\text{ or B)=}(3)/(4)`

Explanation:

The probability of an event is represented by the following equation;

`P(A)=\frac{\text{ Number of favorable outcomes}}{\text{Number of total possible outcomes}}`

Since the events are mutually exclusive, they are called disjoint events. It is given as:

`P(A\text{ or B)=P(A)+P(}B)`

Then, the probability of selecting randomly a student that prefers a cat or a dog:

`\begin{gathered} P(A\text{ or B)=}(16)/(48)+(20)/(48) \\ P(A\text{ or B)=}(36)/(48) \\ P(A\text{ or B)=}(3)/(4) \end{gathered}`