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36. The system of two linear equations given by:2x+4y=1 and x=-2y+1/2hasa. No solutionsb. An infinite number of solutionsc. Possibly several solutionsd. Exactly one solutione. None of the above

User Masaru
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Solution:

Given:


\begin{gathered} 2x+4y=1\ldots\ldots\ldots\ldots\text{.}(1) \\ x=-2y+(1)/(2)\ldots\ldots\ldots\ldots\text{.}(2) \\ \\ R\text{ earranging equation (2);} \\ x+2y=(1)/(2) \\ \text{Multiplying the equation all through by 2;} \\ 2x+4y=1\ldots\ldots\ldots\ldots\ldots(2) \end{gathered}

Since both equations are mathematically the same, then the graph of both linear equations are shown below;

From the above graph given, the system of two linear equations has an infinite number of solutions.

The correct answer is option B.

36. The system of two linear equations given by:2x+4y=1 and x=-2y+1/2hasa. No solutionsb-example-1
User Lulzim Fazlija
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