Given,
The mass of the planet, M=6.5×10²⁴ kg
The radius of the planet, r=70.0×10⁵ m
The gravitational constant, G=6.67×10⁻¹¹ m³kg⁻¹s⁻²
The escape velocity is the minimum initial velocity that an object needs to have in order to escape the gravitational pull of a planet.
The escape velocity is given by,
![v=\sqrt[]{(2GM)/(r)}](https://img.qammunity.org/2023/formulas/physics/college/ebb67nztqgbocje9g6x6awvx4zohwsiowk.png)
On substituting the known values,
![\begin{gathered} v=\sqrt[]{(2*6.67*10^(-11)*6.5*10^(24))/(70.0*10^5)} \\ =11129.75\text{ m/s} \\ =11.13\text{ km/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/8vp592a51pdwfd8n5vij1gl4b0aoazw7xw.png)
Thus the escape velocity of the planet is 11129.75 m/s or 11.13 km/s