Hi there!
We can use implicit differentiation with respect to x:

If a term with 'y' is differentiated, a 'dy/dx' must be included.
We can differentiate each term separately for the explanation.
3xy
We must use the power rule since 'x' and 'y' are both in this term.
Power rule:


Now, we can do the others.
4x
This is a normal power rule derivative.

y²
Since we are not differentiating with respect to y, we must include 'dy/dx'.

Combine the above:

Rearrange to solve for dy/dx.
Move dy/dx to one side:

Factor out dy/dx and divide:
