Question

514507502497495506458478463513sample standard deviation

Answer 1

The sample standard deviation is given by:

`s=\sqrt[]{(1)/(N)\sum^N_(i=1)(x_i-\bar{x})^2}`

Where:

`\begin{gathered} \bar{x}=(514+507+502+497+495+506+458+478+463+513)/(10) \\ \bar{x}=493.3 \end{gathered}`

Therefore:

`\begin{gathered} s=\sqrt[]{(1)/(10)\sum ^(10)_(i=1)(x_i-493.3)^2} \\ s\approx20.155 \end{gathered}`