Question

What is the initial value in the equation f(x) = 350(1 - 0.12)^x? *

Answer 1

Given:

The function is:

`f(x)=350(1-0.12)^x`

To find:

The initial value of the function.

Solution:

We have,

`f(x)=350(1-0.12)^x`

The value of the function at x=0 is called the initial value of the function.

For x=0, we get

`f(0)=350(1-0.12)^0`

`f(0)=350(0.88)^0`

Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.

`f(0)=350(1)`

`f(0)=350`

Therefore, the initial value of the function is 350.