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The cost of demolition vehicles in an action movie is shown in the table. Demolition Vehicles Number Cost ($) 1 350 2. 550 3 750 5 1150 Which of the following is the relation of C, cost, and n, number of vehicles? C = 200n + 150 C = 100n + 250 C = 150n + 200 C = 150n + 100

The cost of demolition vehicles in an action movie is shown in the table. Demolition-example-1
User Francy
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1 Answer

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n = number of vehicle

C = cost

Therefore,


C=200n+150

Just input the n values to the equation and see if you will get the resulting cost C. The equation is definitely,

C = 200n + 150

User CMinus
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