Recall that the slope-intercept form of the equations of a line is:
![y=mx+b\text{.}](https://img.qammunity.org/2023/formulas/mathematics/high-school/72dedp0ao3gfk3qjt7orwcbum87et6bofk.png)
Taking both equations to their slope-intercept form we get:
![\begin{gathered} 6x+6y-6x=-30-6x, \\ 6y=-30-6x, \\ (6y)/(6)=-(30)/(6)-(6)/(6)x, \\ y=-x-5\text{.} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/e02xx9wkishx7m7zl76wlw558r4tb1hvlu.png)
![\begin{gathered} 3x+3y-3x=-15-3x, \\ 3y=-15-3x, \\ (3y)/(3)=-(15)/(3)-(3)/(3)x, \\ y=-x-5. \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/d4yb0ego01p73ybxchd7i3dbq7nat2wncv.png)
Notice that both equations are the same, therefore the system has infinitely many solutions, therefore it is consistent and dependent.
Answer:
Equations:
![\begin{gathered} y=(-1)x+(-5), \\ y=(-1)x+(-5)\text{.} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/8p9pc3080lslvv6lgnwdi7mqvg5jvey4zm.png)
The system is consistent and dependent.
A solution to the system is (0,-5).