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When 200. mL of water are added to 100. mL of 12% KCl solution the final concentration of KCl is (Assume the volumes add.)12%.6.0%.8.0%.36%.4.0%

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In this question, we have a dilution situation, in which we have an amount of volume of a solution, and we are diluting it with more water, which will then cause the concentration of the substance to decrease.

We have 100 mL and 12% KCl, which for a better understanding we can read 12 grams of KCl

We are adding 200 mL:

100 mL = 12 % or grams

300 mL = x % or grams

100x = 0.04

x = 0.04/100

x = 4.0%, therefore the correct answer will be letter E

User Mr Alemi
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