Question

Jabal and Michael are walking to school and agree to leave their homes at the same time.

Jabal leaves his house walking 2.5 meters per second. Michael leaves his house walking 5 meters per second.
Jabal's house is 15 meters closer to school than Michael's house, therefore he is starting 15 meters closer than Michael.
After how long are the boys walking together? Use any strategy you'd like to solve.

Answer 1

6 sec

Explanation:

Let d = distance for Jabal

d + 15 = distance for Michael

t = d/r

d/2.5 = time for Jabal

(d + 15)/5 = time for Michael

The times are equal since they both started walking at the same time.

(d + 15/5 = d/2.5

2.5(d + 15) = 5d

2.5d + 37.5 = 5d

37.5 = 2.5d

d = 15 m. = Jabal's distance

15/2.5 = 6 sec.

Answer 2

Answer: 6 seconds

Explanation:

Time Jabal (2.5mps) Michael (5mps)

Start 15 0

1 sec 17.50 5

2 20 10

3 22.5 15

4 25 20

5 27.5 25

6 30 30

7

8

9

10