
Step-by-step explanation:
(fohog)(x): we would replace the value of x in g(x) with the h(x) function.
Then the result we would replace with the x value in f(x) function
g(x) = x - 2
h(x) = 4x - 1
(hog)(x) = 4(x-2) -1
(hog)(x) = 4x - 8 - 1 = 4x - 9
we replace x in f(x) with the value we got in (hog)(x)
f(x) = (x+4)/x

